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find the HCF of 54 and 81 by prime factorization method. pls send the photo​

Sagot :

3║54, 81

3║18, 27

3║9, 9

3║3, 3

3║1, 1

HCF = 27

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Answer:

Hello,

Step-by-step explanation:

[tex]\begin{array}{c||c}\begin{array}{c|c}54&2\\27&3\\9&3\\3&3\\1\\\end{array}&\begin{array}{c|c}81&3\\27&3\\9&3\\3&3\\1\\\end{array}\end{array}\\\\54=2^1*3^3\\ 81=3^4\\\\\boxed{HCF(54,81)=3^3=27}\\[/tex]