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A nurse is preparing to administer cefaclor 40 mg/kg/day PO divided in equal doses every 8 hr to a child who weighs 48 lb. Available is cefactor
suspension 375 mg/5 ml. How many mL should the nurse administer per dose? (Round the answer to the nearest tenth. Use a leading zero if it
applies. Do not use a trailing zero.)

Sagot :

This question is solved by proportions.

Step 1:

A nurse is preparing to administer cefaclor 40 mg/kg/day.

This means that the first step is finding the baby's weight in kg.

The child weighs 48lb. Each lb has 0,453592kg.

So the child weighs 48*0.453592 = 21.7724kg.

Step 2:

Here, we find the daily dose.

For each kg, the baby is administered 40 mg.

Since the baby weighs 21.7724 kg, the daily dose is of 40*21.7724 = 870.896 mg.

Step 3:

Here, we find how many mL in a day.

For 375 mg, 5 mL are administered. How many mL for 870.896 mg?

375 mg - 5 mL

870.896 mg - x mL

Applying cross multiplication:

[tex]375x = 5*870.896[/tex]

[tex]x = \frac{5*870.896}{375}[/tex]

[tex]x = 11.6[/tex]

Step 4:

Here, we find how many mL per dose.

Equal doses every 8 hours, so 24/8 = 3 doses per day.

11.6/3 = 3.9

Thus, the nurse should administer 3.9 mL per dose.

For more on proportional variables, you can check https://brainly.com/question/23536327.

Answer:

x = 3.9 ml  quantity of ml / dose

Step-by-step explanation:

The child weighs 48 lbs.

Then the weigh in kgs is  48 * 0.454 = 21.792 kgs  (since 1000 lbs = 454 kgs)

If the nurse has to prepare doses according to 40 mg/kg/day then for a child of 21.792 kgs it is needed  21.792*40 mg or 871.68 mg/day, and the fact that he or (she) need to take three doses then each dose will be  of

871.68/3 = 290.56 mg

So far we know that each dose should contain 290.56 mg, now we have the cefactor in a suspension wich density is 375 mg/5 ml or 75 mg/ml

Then by rule of three

if              75  mg     ⇒   1 ml

        290.56 mg     ⇒     x (ml)

x = 290.56/75  ( mg*ml)/ mg

x = 3.87 ml round to the nearest tenth

x = 3.9 ml

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