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find the probability of rolling a sum of a three first and then a sum of nine when a pair of dice is rolled twice

Sagot :

Answer:

Step-by-step explanation:

favorable events for a sum of 3 are 12,21

P(sum 3)=2/36=1/18

favorable events for a sum of 9 are 36,63,45,54

P(sum of 9)=9/36=1/4

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