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Given the function g(x) = x^2 – 10x + 19, determine the average rate of change of
the function over the interval 3 < x < 6.

Sagot :

Answer:

- 1

Step-by-step explanation:

The average rate of change of g(x) in the close interval [ a, b ] is

[tex]\frac{g(b)-g(a)}{b-a}[/tex]

Here [ a, b ] = [ 3, 6 ] , then

g(b) = g(6) = 6² - 10(6) + 19 = 36 - 60 + 19 = - 5

g(a) = g(3) = 3² - 10(3) + 19 = 9 - 30 + 19 = - 2

average rate of change = [tex]\frac{-5-(-2)}{6-3}[/tex] = [tex]\frac{-5+2}{3}[/tex] = [tex]\frac{-3}{3}[/tex] = - 1

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