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Rewrite the expression as the algebraic expression in x
Sin
(tan^-1(x))

Sagot :

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Answer:

  sin(tan^-1(x)) = x/√(x² +1)

Step-by-step explanation:

We know that for an angle in a right triangle...

  Tan = Opposite/Adjacent

and

  Sin = Opposite/Hypotenuse

so we can let Opposite = x and Adjacent = 1. The Pythagorean theorem tells us that ...

  Hypotenuse² = Opposite² + Adjacent² = x² +1

Then the sine of the angle is ...

  sin(tan^-1(x)) = x/√(x² +1)

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