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the sum of numerator and denominator of the fraction is 12 and the denominator is 2 more than numerator.find the fraction



Sagot :

Let numerator be x

  • Denominator=x+2

ATQ

[tex]\\ \sf\longmapsto x+x+2=12[/tex]

[tex]\\ \sf\longmapsto 2x+2=12[/tex]

[tex]\\ \sf\longmapsto 2x=12-2[/tex]

[tex]\\ \sf\longmapsto 2x=10[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{10}{2}[/tex]

[tex]\\ \sf\longmapsto x=5[/tex]

Now the fraction is

[tex]\\ \sf\longmapsto \dfrac{x}{x+2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{5}{5+2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{5}{7}[/tex]

-- Their sum is 12.

-- If they were equal, each would be 6.

-- To make them differ by 2 without changing their sum, move 1 from the numerator (make it 5), to the denominator (make it 7).