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dy/dx(2x^2+2y^2-3x+2y=1)​

Sagot :

Answer:

[tex]{ \bf{ \frac{dy}{dx} = \frac{3 - 4x}{4y + 2} }}[/tex]

Step-by-step explanation:

[tex]{ \sf{ \frac{dy}{dx} (2 {x}^{2} + 2 {y}^{2} - 3x + 2y = 1) }} \\ \\ { \sf{4x + 4y \frac{dy}{dx} - 3 + 2 \frac{dy}{dx} = 0 }} \\ \\ { \sf{ 4y\frac{dy}{dx} + 2 \frac{dy}{dx} = 3 - 4x }} \\ \\ { \sf{ \frac{dy}{dx}(4y + 2) = 3 - 4x }} \\ \\ { \sf{ \frac{dy}{dx} = \frac{3 - 4x}{4y + 2} }}[/tex]

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