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Sagot :
Given that
U = {X : 30 ≤ X ≤ 40. X is an even number}.
so Mathematically
U = {30,32,34,36,38 40}.
P = {X : X is a multiple of 4}
P = { 4,8,12,16,20,24,28,32,36,40,44,........}
and Q = {X : X is a number such that the sum of its digits is an odd number}.
Q = {12,14,16,18,21,23,25,27,29,30,32,34,36,38,41,43,45,..........}.
(Q')= U-Q ={40}
(P∩Q')= {40}
n(P∩Q')= 1
(Q') is Q complement which means a set containing those elements of the universal set which are not element of the set Q.
(P∩Q') is a set containing those elements of set P and Q complement which are common to both sets.
n(P∩Q') denotes the number of elements in a set containing those elements of set P and Q complement which are common to both sets which has only 1 element which is 40.
So the best answer is part A = 1.
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