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Sagot :
Answer:
13i/5
Step-by-step explanation:
25z^2+140=-29 subtract 140 from both sides
25z^2=-169 now square root both sides.
[tex]\sqrt{25z^{2} }[/tex]=[tex]\sqrt{-169}[/tex] a negative root forms i
5z=13i
z=13i/5
Answer:
z is 13i/5
Step-by-step explanation:
[tex]{ \sf{25 {z}^{2} + 140 = - 29}} \\ { \sf{25 {z}^{2} = - 169 }} \\ { \sf{ \sqrt{25 {z}^{2} } = \sqrt{ - 169} }} \\ { \sf{5z = \sqrt{169 \times - 1} }} \\ { \sf{5z = \sqrt{169} \times \sqrt{ - 1} }} \\ { \sf{5z = 13 \times \sqrt{ {i}^{2} } }} \\ { \sf{5z = 13i}} \\ { \sf{z = \frac{13i}{5} }}[/tex]
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