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Answer:
Hello,
We don't need vw(x) !
[tex]w^{-1}(x)=\dfrac{x-1}{2}[/tex]
Step-by-step explanation:
[tex]w(x)=2x+1=y\\\\2y+1=x \ exchanging \ x\ and\ y\\\\y=\dfrac{x-1}{2} \\\\w^{-1}(x)=\dfrac{x-1}{2}[/tex]