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Find two different integers such that the square of the integer is 12 less than seven times the integer

Sagot :

9514 1404 393

Answer:

  3, 4

Step-by-step explanation:

If x represents the integer, then the relationship required is represented by the equation ...

  x^2 = 7x -12

  x^2 -7x +12 = 0 . . . . put in standard form

  (x -3)(x -4) = 0 . . . . . factor

The values of x that make this relation true are x=3 and x=4.

The two integers are 3 and 4.

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