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Answer:
0, 5, 10, 15, 20
0, 5, 40, 405, 5,120
Step-by-step explanation:
One rule can be "add 5 to the previous term to get the next term."
0, 5, 10, 15, 20
Second rule:
For each term number 1, 2, 3, ..., n,
each term = 5(n - 1)^n
0, 5, 40, 405, 5,120
The next three terms for the rule Tn = a + (n-1)d will be 10,15 and 20
The next three terms for rule 5(n-1)ⁿ will be 40, 405 and 5120.
Sequences are numbers arranged in a specific pattern.
Given the sequence 0, 5...
This sequence can be an arithmetic sequence with nth term expressed as:
a is the first term = 0
n is the number of terms
d is the common difference = 5 - 0 5
If n = 3
T3 = 0 + (3-1)*5
T3 = 2 * 5
T3 = 10
If n = 4
T4 = 0 + (4-1)*5
T4 = 3 * 5
T4 = 15
If n = 5
T5 = 0 + (5-1)*5
T5 = 4 * 5
T5 = 20
Hence the next three terms for the rule will be 10,15 and 20
Also, we can also use the recursive rule f(n) = 5(n-1)ⁿ
If n = 3
f(3) = 5(3-1)³
f(3) = 5(2)³
f(3) = 5 * 8
f(3) = 40
If n = 4
f(4) = 5(4-1)⁴
f(4) = 5(3)⁴
f(4) = 5 * 81
f(4) = 405
If n = 5
f(5) = 5(5-1)⁵
f(5) = 5(4)⁵
f(5) = 5 * 81
f(5) = 1024 * 5
f(5) = 5120
Hence the next three terms for the rule will be 40, 405, and 5120.
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