IDNLearn.com is your reliable source for expert answers and community insights. Join our community to receive prompt and reliable responses to your questions from experienced professionals.

Solve for
x. Round to the nearest tenth of a degree, if necessary.


Solve For X Round To The Nearest Tenth Of A Degree If Necessary class=

Sagot :

Answer:

[tex]\displaystyle x \approx 30.8[/tex]

Step-by-step explanation:

Note that the figure is a right triangle, and that we are given the length of the side adjacent to x and the hypotenuse of the triangle.

Therefore, we can use the cosine ratio. Recall that:

[tex]\displaystyle \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}[/tex]

The adjacent side is 8.5 and the hypotenuse is 9.9. Therefore:

[tex]\displaystyle \cos x = \frac{8.5}{9.9}[/tex]

We can take the inverse cosine of both sides:

[tex]\displaystyle x = \cos^{-1} \frac{8.5}{9.9}[/tex]

Use a calculator. Hence:

[tex]\displaystyle x \approx 30.8[/tex]

30 is the answer get me