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Let (2,-5) be a point on the terminal side of theta find the exact values of cos theta csc theta and tan theat

Sagot :

DWReadidn

Answer:

Step-by-step explanation:

x = 2, y = -5

√(2²+(-5)²) = √29

cosθ = 2/√29 = (2√29)/29

sinθ = -5/√29

cscθ = 1/sinθ = -√29/5

tanθ = sinθ/cosθ = -5/2

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View image DWRead

The values of cos theta is 2/[tex]\sqrt{29}[/tex] , cosec theta is [tex]\sqrt{29} /5[/tex] and tan theta is 5/2 if the point on the terminal side of theta is (2,-5).

What is pythagoras theorem?

It says that in a right angled triangle the square of the hypotenuse is equal to the sum of the square of base and square of height.

How to find values of trigonometric function?

We have been given a point (2,-5) on the terminal side. Let us plot the point on the graph and join it with origin from both ends.

By pythagoras theorem we can easily find AC=[tex]\sqrt{5^{2}+2^{2} }[/tex]

AC=[tex]\sqrt{29}[/tex]

With the help of the sides of the triangle we can find the value of

cos theta=2/[tex]\sqrt{29}[/tex]

cosec theta=[tex]\sqrt{29}[/tex]/5

tan theta=5/2

Hence the values of cos theta, cosec theta, tan theta are 2/[tex]\sqrt{29}[/tex],[tex]\sqrt{29}[/tex]/5,5/2 respectively.

Learn more about pythagoras theorem at https://brainly.com/question/343682

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