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The area of a rectangle is given by the trinomial y^ 2 +4y-45. If the length of the rectangle is y + 9 , what is the width of the rectangle?

Sagot :

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Step-by-step explanation:

Area of rectangle =L×W

Width =Area

[tex]w idth= \frac{area \ }{length} \\ \\width = \frac{ {y}^{2} + 4y - 45}{y + 9} \\ \\ = \frac{(y - 5)(y + 9)}{(y + 9)} \\ \\ width = y - 5[/tex]

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