Answer:
Step-by-step explanation:
[tex]a = \frac{2b+1}{3b-1}[/tex]
b = 2/3
[tex]2b + 1 = 2*\frac{2}{3}+1\\\\=\frac{4}{3}+1\\\\=\frac{4}{3}+\frac{3}{3}\\\\=\frac{7}{3}\\\\3b-1 = 3*\frac{2}{3}-1\\\\=2- 1 = 1\\\\\\[/tex]
[tex]a = \frac{2b+1}{3b-1}\\\\a=\frac{\frac{7}{3}}{1}\\\\=\frac{7}{3}\\\\[/tex]
a = 7/3
b)
[tex]\frac{2b+1}{3b-1}=a\\\\[/tex]
Cross multiply,
2b + 1 = a*(3b - 1)
2b + 1 = a*3b - 3*a
2b + 1 = 3ab- 3a
2b = 3ab - 3a - 1
2b - 3ab = -3a - 1
b(2 - 3a) = -3a - 1
[tex]b =\frac{-3a - 1}{2 - 3a}[/tex]
