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16-32)
What is the equation of the line that is perpendicular to
the given line and passes through the point (3, 0)?
O 3x + 5y = -9
O 3x + 5y = 9
O 5x - 3y = -15
O 5x - 3y = 15


1632 What Is The Equation Of The Line That Is Perpendicular To The Given Line And Passes Through The Point 3 0 O 3x 5y 9 O 3x 5y 9 O 5x 3y 15 O 5x 3y 15 class=

Sagot :

Answer:

the fourth option : 5x - 3y = 15

Step-by-step explanation:

the slope of the original line is given by the coordinate differences between the 2 points on the line.

remember, the slope is the factor of x in the line equation and is the ratio y/x indicating how many units y is changing, when x changes a certain number of units.

so, to go from (-3. 2) to (2, -1) x changes 5 units and y -3 units.

therefore, the slope is -3/5.

the slope of a perpendicular line simply switched x and y. and the sign of the slope.

therefore the slope of the perpendicular line is 5/3.

and the line equation is

y = (5/3)x + c

to get c we need the point on the line (3, 0).

0 = (5/3)×3 + c = 5 + c

c = -5

y = (5/3)x - 5

3y = 5x - 15

3y - 5x = -15 or (after multiplying both sides by -1)

5x - 3y = 15