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A 6.0-L vessel was found to contain 1.0 mol BrCl 3 , 2.0 mol Br 2 and 6.0 mol Cl 2 at equilibrium. What is the equilibrium constant, K c , for this equilibrium mixture for the reaction 2BrCl 3 (g) Br 2 (g) 3Cl 2 (g)

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Answer:

Writing a balanced Equation for the reaction

Br₂ + 3Cl₂ ==> 2BrCl₃

Kc = [BrCl₃]² / [Br₂][Cl₂]³

Each Concentration (n) = moles/volume of container.

(nBrCl₃)= 1/6 = 0.167moldm-³

(nBr₂) = 2/6 = 0.333moldm-³

(nCl₂) = 6/6 = 1moldm-³

Kc = (0.167)² / (0.333)(1)³

Kc = 0.0838.

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