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Answer:
A
Step-by-step explanation:
tan(3x/4)=sin(3x/4)/cos(3x/4)
So the domain of tah(3x/4) is all real numbers except real numbers that make cos(3x/4)=0.
cos(pi/2 +n pi)=0
So we need to solve 3x/4=pi/2+n pi
Multiply both sides by 4/3: x=4/3(pi/2+n pi)
Distribute: x=2pi/3+4n pi/3
Or x=(2pi+4 n pi)/3
Or x=2 pi/3 ×(1+2n)
So odd integer multiples of 2pi/3 is the numbers to be excluded from the domain.
The required domain of the function y = 5/3 tan(3/4x) is (-∞, ∞) - {- 2/3 (2n + 1)π, 2/3 (2n + 1)π}.
These are the equation that contains trigonometric operators such as sin, cos.. etc.. In algebraic operation.
y = 5/3 tan(3/4x)
Function tan defined at every x except x = nπ/2 where n = odd number. i.e x = (-∞,∞) - {(2n+1) * π/2, -(2n+1) * π/2}
3/4 * x = (2n + 1 ) * π/2
x = (2n + 1) * 4/3* π/2
x = 2/3 (2n + 1)π
So the required domain for the given function y = 5/36tan(3/4)x is given as,
Domain (x) = (-∞, ∞) - {- 2/3 (2n + 1)π, 2/3 (2n + 1)π}.
Thus, the required domain of the function y = 5/3 tan(3/4x) is (-∞, ∞) - {- 2/3 (2n + 1)π, 2/3 (2n + 1)π}.
Learn more about trigonometry equations here:
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