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Strontium-90 has a half-life of about 28 years. Which equation will solve the problem of how many grams of a 40 g sample
will remain after 84 years?
Oy = }(40)
y = {(40)
Oy = 40(1)
y = 40()
84

Sagot :

Gadu0722idn

Answer:a0 = 40 mg

a1 = 20 mg  after 28 years

a2 = 10 mg  after another 28 years

Step-by-step explanation:Set this up as

10 = 40 (1/2)t/28

and solve for t in years.

10/40 = (1/2)t/28

log(0.25) = (t/28) log(0.5)

t = 28 log(0.25) / log(0.5) years = 56 years

1blackbeltprincessidn

Answer:

40 mg

Step-by-step explanation:

10 = 40 (1/2)t/28   and solve for t in years.   10/40 = (1/2)t/28   log(0.25) = (t/28) log(0.5)   t = 28 log(0.25) / log(0.5) years = 56 years

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