Answer: No, the given point does not make the equation true.
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Explanation:
There are three different ways to approach this.
One way is to plug x = 3 into the equation to find that
y = 5x
y = 5*3
y = 15
But that doesn't match up with y = 3 from the point (3,3). So we see that (3,3) is not a solution to y = 5x.
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Or another method we could do is plug x = 3 and y = 3 to find a contradiction
y = 5x
3 = 5*3
3 = 15
The contradiction being that 3 on the left side doesn't match with 15 on the right side. The false equation at the end means y = 5x is false for (x,y) = (3,3), and therefore this point is not a solution to y = 5x.
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The third method involves graphing the line y = 5x. You can see that (3,3) is not on the line, which visually confirms the results of the previous two sections. So for a point to be a solution, it must be on the line.
