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The one-to-one functions g and h are defined as follows.
g={(-9, 2), (-1, -3), (2, 3), (9, 4)}
h(x) = 3x-4
Find the following.
g^-1 (2) =?
h^-1 (x) =?
(h • h^-1) (2) =?

Sagot :

Caylusidn

Answer:

Hello,

Step-by-step explanation:

[tex]g(-9)=2\Longrightarrow\ g^{-1}(2)=-9\\\\y=h(x)=3x-4\\x=3y-4\\\\y=\dfrac{x+4}{3} \\\\h^{-1}(x)=\dfrac{x+4}{3}\\\\h(h^{-1}(x))=(h^{-1}o\ h)(x)=1_\pi(x) \ (identical\ permutation\ of\ plane) \\\\h(h^{-1}(2))=2[/tex]

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