Join the IDNLearn.com community and start finding the answers you need today. Get the information you need from our community of experts, who provide detailed and trustworthy answers.
Sagot :
Answer:
[tex]\boxed {\boxed {\sf B. \ 1170 \ Joules }}[/tex]
Explanation:
We are asked to find how much heat a sample of copper absorbs when the temperature is increased.
Since we know the mass, temperature increase, and specific heat capacity, we can use the following formula to calculate heat.
[tex]q= mc \Delta T[/tex]
The mass of the copper sample is 100 grams, the temperature is changed or increased by 30.0 degrees Celsius, and the specific heat of copper is 0.39 Joules per gram degrees Celsius.
- m= 100 g
- c= 0.39 J/g °C
- ΔT= 30.0 °C
Substitute the values into the formula.
[tex]q= (100 \ g )(0.39 \ J/g \textdegree C ) (30.0 \textdegree C )[/tex]
Multiply the first two values. Note that the units of grams cancel.
[tex]q= 39 \ J/ \textdegree C (30.0 \textdegree C )[/tex]
Multiply again, this time the units of degrees Celsius cancel.
[tex]q= 1170 \ J[/tex]
The copper sample absorbs 1170 Joules of heat and Choice B is correct.
Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.