Join the conversation on IDNLearn.com and get the answers you seek from experts. Get prompt and accurate answers to your questions from our community of experts who are always ready to help.

Light of wavelength 600 nm illuminates a diffraction grating. The second-order maximum is at angle 39.2. How many lines per millimeter does this grating have?

Sagot :

Answer:

Diffraction equation applies in this case:

d*Sin x = m*wavelength, where d = spacing of lines, x = angle = 39.5°, m = order of maximum = 2

Substituting;

d* Sin 39.5 = 2*600*10^-9

d = (2*600*10^-9)/Sin 39.5 = 1.88656*10^-6 m

In 1 mm (or 0.001 m), the number of lines is given as;

Number of lines = 0.001/d = 0.001/(1.88656*10^-6) = 530.065 ≈ 530 lines