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If h(x) = x2-5x + 7 find:
⅓ h(-8)

Sagot :

Theleangreenbeanidn

Answer:

[tex]\displaystyle \frac{1}{3} h(-8) = 37[/tex]

Step-by-step explanation:

Hi there!

[tex]h(x) = x^2-5x + 7[/tex]

First, find h(-8) by replacing all of [tex]x[/tex] with -8:

[tex]h(-8) = (-8)^2-5(-8) + 7\\h(-8) = 64+40 + 7\\h(-8) = 111[/tex]

Now, find ⅓ h(-8) by multiplying the entire expression by ⅓:

[tex]\displaystyle \frac{1}{3} h(-8) = 111 * \frac{1}{3} \\\\\displaystyle \frac{1}{3} h(-8) = 37[/tex]

I hope this helps!

Woofpuppidn
1/3 (h(-8)) = 37. hope this helped
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