Answer:
[tex]\displaystyle \frac{1}{3} h(-8) = 37[/tex]
Step-by-step explanation:
Hi there!
[tex]h(x) = x^2-5x + 7[/tex]
First, find h(-8) by replacing all of [tex]x[/tex] with -8:
[tex]h(-8) = (-8)^2-5(-8) + 7\\h(-8) = 64+40 + 7\\h(-8) = 111[/tex]
Now, find ⅓ h(-8) by multiplying the entire expression by ⅓:
[tex]\displaystyle \frac{1}{3} h(-8) = 111 * \frac{1}{3} \\\\\displaystyle \frac{1}{3} h(-8) = 37[/tex]
I hope this helps!
