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How would the expression x^2 -9 be rewritten using Difference of Squares?
O A. (x+3)(x - 3)
O B. (X-9)^2
O C. (x +9)(x-9)
O D. (x+3)^2

Sagot :

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Answer:

A. (x+3)(x - 3)

Step-by-step explanation:

x^2 -9

Rewriting

x^2 - 3^2

We know that a^2 - b^2 = (a-b)(a+b)

(x-3)(x+3)

Answer:

[tex]\left(x+3\right)\left(x-3\right)[/tex]

Step-by-step explanation:

[tex]x^2 -9[/tex]

To factor an integer, we need to divide it by the ascending sequence of primes  (2, 3, 5). The number of times each prime divides the original integer becomes its exponent. [tex]3^{2} =9[/tex]

Now, we need to factor this expression by applying the difference of two squares rule:

[tex]A^{2} -B^{2} =(A+B)(A-B)[/tex]

A= x and B= 3

[tex](x+3)(x-3)[/tex]

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