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Sagot :
Answer:
11.47 m
Explanation:
Givens
vi = 15 m/s
a = - 9.81 m/s^2
vf = 0
d = ?
Formula
vf^2 = vi^2 + 2ad
Solution
0 = (15)^2 + 2*(-9.81)*d
- 225 = 2 * - 9.81 *d
-225 = - 19.62 * d
d = - 225/-19.62
d = 11.47 m
The height of the ceiling in the school gym from the floor is 11.48m.
HOW TO CALCULATE HEIGHT OF A PROJECTILE:
- Using one of the equations of motion as follows:
v² = u² + 2as
Where;
v = final velocity (m/s)
u = initial velocity (m/s)
a = gravitational acceleration (m/s²)
s = distance traveled (m)
According to this question,
- The final velocity (v) of the volleyball is 15m/s
- The initial velocity is 0m/s
- The acceleration due to gravity is 9.8m/s
Using the formula, v² = u² + 2as, the height of the ceiling (s) can be calculated as follows:
15² = 0² + 2 (9.8) (s)
225 = 0 + 19.6s
225 = 19.6s
s = 225/19.6
s = 11.48m
Therefore, the height of the ceiling in the school gym from the floor is 11.48m
Learn more: https://brainly.com/question/21065813
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