Answered

Join the IDNLearn.com community and start getting the answers you need today. Our platform is designed to provide accurate and comprehensive answers to any questions you may have.

Solve the equation by factoring:
X^3 - 9x^2 + 18x = 0

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏxidn

[tex] \large \mathfrak{Solution : }[/tex]

Let's factorise :

  • [tex]x( {x}^{2} - 9x + 18) = 0[/tex]

  • [tex]x( {x}^{2} - 6x - 3x + 18) = 0[/tex]

  • [tex]x( x(x - 6) - 3(x - 6)) = 0[/tex]

  • [tex]x(x - 6)(x - 3) = 0[/tex]

now there are three cases :

1. when, x - 6 = 0

  • x = 6

2. when x - 3 = 0

  • x = 3

3. when x = 0

  • x = 0

i hope it helped...

Answer:

x=0,3,6

Step-by-step explanation:

x³-9x²+18x=0

x(x²-9x+18)=0

x[x²-3x-6x+18]=0

x[x(x-3)-6(x-3)]=0

x(x-3)(x-6)=0

x=0,3,6

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.