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2.)

Two clocks are set at 6 A.M. One clock gains 30 seconds every hour and the second clock
loses 1 minute every hour. At what time will the faster clock be 30 minutes ahead of the
second clock?

Sagot :

   Difference in time of both the clocks after 1 minute will be the sum of gain in time of one clock and delay in time of the second clock in 1 minute.

First clock will be 30 minutes ahead of the second clock in 20 hours.

     It's given in the question,

  • Both the clocks are set at 6 A.M.
  • First clock gains 30 seconds every hour

Since, 1 second = [tex]\frac{1}{60}[/tex] minutes

Therefore, 30 seconds = [tex]\frac{30}{60}[/tex] minutes

                                      = 0.5 minutes

That means first clocks gains 0.5 minutes in every hour.

  • Second clock loses 1 minute every hour

Therefore, difference in both the clocks in every hour = 1 + 0.5

                                                                                           = 1.5 minutes

Difference of 30 minutes will be in the duration = [tex]\frac{30}{1.5}[/tex] hours

                                                                                = 20 hours

              First clock will be 30 minutes ahead of the second clock in 20 hours.

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