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A tourist drags his luggage of mass 20 kg with a force, F at a constant velocity across the floor . The coefficient of kinetics friction between the rollers of the luggage and the floor is 0.40. The luggage is dragged 0.80 m along the floor. Calculate the work done on the luggage by the force, F.​

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The work done on the luggage by the force is 62.78 J

The given parameters;

mass of the luggage, m = 20 kg

coefficient of friction, μ = 0.4

distance moved by the object, d = 0.8 m

To find:

  • the work done on the object by the force

The work done on the luggage by the force is calculated as;

Work-done = F x d

work done = ma x d

[tex]work -done = m\times \mu \times g \times d\\\\work-done = 20 \times 0.4 \times 9.81 \times 0.8\\\\work-done = 62.78 \ J[/tex]

Thus, the work done on the luggage by the force is 62.78 J

Learn more here: https://brainly.com/question/19498865

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