IDNLearn.com is the perfect place to get answers, share knowledge, and learn new things. Ask any question and get a thorough, accurate answer from our community of experienced professionals.

A tourist drags his luggage of mass 20 kg with a force, F at a constant velocity across the floor . The coefficient of kinetics friction between the rollers of the luggage and the floor is 0.40. The luggage is dragged 0.80 m along the floor. Calculate the work done on the luggage by the force, F.​

Sagot :

The work done on the luggage by the force is 62.78 J

The given parameters;

mass of the luggage, m = 20 kg

coefficient of friction, μ = 0.4

distance moved by the object, d = 0.8 m

To find:

  • the work done on the object by the force

The work done on the luggage by the force is calculated as;

Work-done = F x d

work done = ma x d

[tex]work -done = m\times \mu \times g \times d\\\\work-done = 20 \times 0.4 \times 9.81 \times 0.8\\\\work-done = 62.78 \ J[/tex]

Thus, the work done on the luggage by the force is 62.78 J

Learn more here: https://brainly.com/question/19498865

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.