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Sagot :
Step-by-step explanation:
X^(a²-b²+c²-a²+b²-c²) / X^(c(a-b)+b(c-a)+a(b-c))
= X^(0) / X^(ac-bc+bc-ab+ab-ac)
= X^0 / X^0
=1 / 1
= 1
Answer:
- 1
Step-by-step explanation:
- [tex](\frac{x^{a+b}}{x^c})^{a-b}*(\frac{x^{c+a}}{x^b})^{c-a}*(\frac{x^{b+c}}{x^a})^{b-c} =[/tex]
- [tex]\frac{x^{a^2-b^2}}{x^{c(a-b)}}*\frac{x^{c^2-a^2}}{x^{b(c-a)}}*\frac{x^{b^2-c^2}}{x^{a(b-c)}} =[/tex]
- [tex]\frac{x^{a^2-b^2+c^2-a^2+b^2-c^2}}{x^{c(a-b)+b(c-a)+a(b-c)}} =[/tex]
- [tex]\frac{x^0}{x^0} =[/tex]
- 1
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