Answered

IDNLearn.com provides a collaborative environment for finding and sharing knowledge. Discover in-depth and trustworthy answers to all your questions from our experienced community members.

Describe the motion shown in the lines

Sagot :

Lalitac915idn

Answer:

Solution

For figure (a)

During interval AB Velocity is +ve, so the particle is moving in +ve direction, but it is slowing down as acceleration (slope of v-7 curve) is negative.

During interval BC Particle remains at rest as the velocity is zero. Acceleration is also zero.

During interval CD Velocity is -ve, so the particle is moving in -ve direction and is speeding up as acceleration is also negative.

For figure (b),

During interval AB Particle is moving in +ve direction with constant velocity and acceleration is zero.

During interval BC Particle is moving in +ve direction as velocity is +ve, but it slows down until it comes to rest as acceleration is negative.

During interval CD Velocity is -ve so the particle is moving in -ve direction and is speeding up as acceleration is also negatived

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.