Nick1272idn
Answered

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How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 10% ​antifreeze?

To obtain a 10% antifreeze​ solution, _ ​gallon(s) of water should be added.

Sagot :

Biggielittle64idn

Answer:

Let x = amount of water to be added with 0% antifreeze

1 = amount of pure antifreeze at 100%

x+1 = amount of the mixture at 60% antifreeze

Step-by-step explanation:

1= .60x + .60

Subtract .60 from each side:

1-.60 = .60x

.40 = .60x

Divide both sides by .60

Check: Total antifreeze = 1 gallon in total mixture of 1 + 2/3 gallon = 5/3 gallons. 1 gallon divided by 5/3 equals 3/5 which is 60%. It checks.

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