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There are 7 unique names in a bowl. In how many orders can 2 names be chosen? Hint: The word orders
implies that each unique order of two names is counted as a possibility.

Sagot :

Masojeanthony379idn

Answer:

2/7

Step-by-step explanation:

Probability=number of names chosen/total number of names

p=2/7

Here in this question order is mentioned so we will use permutation.

and the formula is P(n,r) = [tex]\frac{n!}{(n-r)!}[/tex]

What is permutation and combination ?

When the order of selecting something doesn't matter we use combination and when order of selection matters we use permutation.

In the given question number of unique names (n) = 7 and we are taking 2 names at a time.So the permutation of 7 names takes 2 at a time is P(7,2) =

[tex]\frac{7!}{(7-2)!}[/tex] = [tex]\frac{7!}{5!}[/tex] = [tex]\frac{7*6*5*4*3*2*1}{5*4*3*2*1}[/tex] = 7x6 = 56.

So, the number of ways of selecting is 56.

Learn more about Permutations and Combinations here :

https://brainly.com/question/13387529

#SPJ2

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