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The square root of x minus two plus 8 equals x

Sagot :

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Step-by-step explanation:

[tex] \sqrt{x - 2 + 8} = \sqrt{x + 6} = x[/tex]

[tex] {( \sqrt{x + 6} })^{2} = {x}^{2} [/tex]

[tex]x + 6 = {x}^{2} [/tex]

[tex] {x}^{2} - x - 6 = 0[/tex]

[tex](x - 3)(x + 2) = 0[/tex]

x = 3 or x = -2 we dont use the (-2) because we have a sqrt

So x =3

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