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Sagot :
Answer:
t = 1
Step-by-step explanation:
the greatest velocity could be reached:
v' = 0
12 - 12t =0
or 12t =12
t = 12/12
t = 1
v=12t-6t^2
Find derivative of v
[tex]\\ \sf\longmapsto \dfrac{dv}{dx}[/tex]
[tex]\\ \sf\longmapsto \dfrac{d}{dx}12t-6t^2[/tex]
[tex]\boxed{\sf \dfrac{d(x^n)}{dx}=nx^{n-1}}[/tex]
[tex]\\ \sf\longmapsto 12-12t[/tex]
Let it be 0
[tex]\\ \sf\longmapsto 12-12t=0[/tex]
[tex]\\ \sf\longmapsto 12=12t[/tex]
[tex]\\ \sf\longmapsto t=\dfrac{12}{12}[/tex]
[tex]\\ \sf\longmapsto t=1s[/tex]
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