IDNLearn.com provides a user-friendly platform for finding and sharing knowledge. Our experts are available to provide accurate, comprehensive answers to help you make informed decisions about any topic or issue you encounter.
Sagot :
We have that it takes the ball [tex]t=0.553sec[/tex] to take to hit the ground
[tex]t=0.553sec[/tex]
From the Question we are told that
Initial height [tex]s=1.5m[/tex]
Generally the equation for Time is mathematically given as
[tex]S=ut+1/2at^2\\\\1.5=0.5*9.8[/tex]
[tex]t=0.553sec[/tex]
For more information on this visit
https://brainly.com/question/22271063?referrer=searchResults
The paper ball will hit the ground from 1.5 m at 0.55 s.
Here we can use the free fall kinematics equations. Let's see that the paper ball falls from the rest, so the initial velocity will be 0.
[tex]y=y_{i}+v_{i}t-0.5gt^{2}[/tex]
Here:
- y is the final height
- y(i) is the initial height
- v(i) initial velocity (will be 0)
- g is the gravity (9.81 m/s²)
- t the time
Now, the initial height will be 1.5 m, putting our reference system zero in the ball. So, the final height will be 0 m, because it hits the ground.
[tex]0=1.5-0.5(9.81)t^{2}[/tex]
Therefore, we just need to solve it for t.
[tex]t=\sqrt{\frac{3}{9.81}}[/tex]
[tex]t=0.55\: s[/tex]
The ball will hit the ground at 0.55 s.
You can learn more about free fall motion here:
https://brainly.com/question/17610229
I hope it helps you!
We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the solutions you’re looking for. Thanks for visiting, and see you next time for more reliable information.