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Sagot :
Answer: 60
Step-by-step explanation:
[tex]\large \boldsymbol{} \sf 6=\bold3\cdot \underline2 \\\\12=\bold3\cdot \underline2\cdot 2\\\\15=5\cdot\bold 3 \\\\ LCM(6 ; 12 ; 15) =\bold{3\cdot 2}\cdot 2\cdot 5=60[/tex]
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