IDNLearn.com provides a collaborative platform for sharing and gaining knowledge. Our experts provide timely and precise responses to help you understand and solve any issue you face.
Answer: 5 and 14.
Step-by-step explanation:
We know that the Raiders and Wildcats both scored the same number of points in the first quarter so let a,a+d,a+2d,a+3d be the quarterly scores for the Wildcats. The sum of the Raiders scores is a(1+r+r^{2}+r^{3}) and the sum of the Wildcats scores is 4a+6d. Now we can narrow our search for the values of a,d, and r. Because points are always measured in positive integers, we can conclude that a and d are positive integers. We can also conclude that $r$ is a positive integer by writing down the equation:
a(1+r+r^{2}+r^{3})=4a+6d+1
Now we can start trying out some values of r. We try r=2, which gives
15a=4a+6d+1
11a=6d+1
We need the smallest multiple of 11 (to satisfy the <100 condition) that is 1 (mod 6). We see that this is 55, and therefore a=5 and d=9.
So the Raiders' first two scores were 5 and 10 and the Wildcats' first two scores were 5 and 14.