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Solve for x: −2x + 5 < 7
x > −1
x < −1
x > −6
x < −6

Sagot :

[tex]\\ \sf\longmapsto -2x+5\lt 7[/tex]

[tex]\\ \sf\longmapsto -2x\lt 7-5[/tex]

[tex]\\ \sf\longmapsto -2x\lt 2[/tex]

[tex]\\ \sf\longmapsto x\lt \dfrac{2}{-2}[/tex]

[tex]\\ \sf\longmapsto x\lt -1[/tex]

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Step-by-step explanation:

-2x+5<7

by subtracting 5 from both sides, we get

-2x+5-5<7-5

-2x<2

After dividing both sides by -2, the comparing sign changes and we get

-2x/-2>2/-2

x>-1

Hence, first option is correct.

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