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The empirical formula of compound X is
From the analysis, we have the following information about the composition of compound X by mass; 40.00% C, 6.71% H, and 53.29% O
Hence, to find the empirical formula of compound X ;
C - 40.00/12 H - 6.71/1 O - 53.29/16
C - 3.33 H - 6.71 O - 3.33
Dividing through by the lowest ratio;
C - 3.33/3.33 H - 6.71/3.33 O - 3.33/3.33
C - 1 H - 2 O - 1
Empirical formula of the compound X is CH2O
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