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Answer:
[tex]y=-\frac{8}{3}x+\frac{1}{3}[/tex]
Step-by-step explanation:
[tex]\frac{y-3}{x-(-1)} =\frac{-5-3}{2-(-1)} \\\frac{y-3}{x+1} =\frac{-8}{3} \\3y-9=-8x-8\\3y=-8x+1\\y=-\frac{8}{3}x+\frac{1}{3}[/tex]