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Jason is pulling a box across the room. He is pulling with a force of 14 newtons and his arm is making a 48 angle with the horizontal, what is the vertical component of the force he is pulling with?

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Whitneytr12idn

When Jason pulls a box with a force of 14 N, making a 48 angle between his arms and the horizontal, the vertical component of the force he is pulling is 10.40 N.

We can calculate the vertical component imaging a right triangle with the following dimensions:

H: is the hypotenuse = applied force (F) = 14 N (in the direction of Jason's arms)

A: is the adjacent side = horizontal component of the force

O: is the opposite side = vertical component of the force =?  

θ: is the angle with the horizontal = 48°

Hence, we can find the vertical component with the following trigonometric function:

[tex] sin(\theta) = \frac{O}{H} [/tex]

[tex] O = sin(\theta)*H = sin(48)*14 N = 10.40 N [/tex]

Therefore, the vertical component of the force he is pulling is 10.40 N.

You can see more about force here: https://brainly.com/question/14131556?referrer=searchResults

I hope it helps you!  

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