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The coordinates of an image dilated about the origin is given by multiplying the coordinates of the preimage by the scale factor
The coordinates where P' should be is (-6.5, 4.5)
The reason the above values is correct is as follows:
Question: The diagram in the question appear missing, a sample diagram of a trapezoid PQRS, having coordinates; P(-3, 3), Q(6, 3), R(9, 0), S(-5, 0)
The coordinates of the vertices of the image are multiplied using the given scale factor about the origin and 2 is subtracted from the x-values the as follows;
The coordinates of the image as follows;
[tex]\begin{array}{|l|cl|}Preimage \ (x, y)&&Image = \left (x \times \dfrac{3}{2} - 2,\ y \times \dfrac{3}{2} \right)\\P(-3, \ 3)&&P'(-6.5, \ 4.5)\\Q(6, \ 3)&&Q'(7, \ 4.5)\\R(9, \ 0)&&R'(11.5, \ 0)\\S(-5, \ 0)&&S'(-9.5, \ 0)\end{array}\right][/tex]
Therefore, the coordinates where P' should be is (-6.5, 4.5)
Learn more about scale drawing about the origin here:
https://brainly.com/question/10618542
