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Answer:
[tex] x_{1} = 0. \: \: \: x_{2} = 4[/tex]
Step-by-step explanation:
[tex]3(x - 2)^{2} + 1 = 3[/tex]
[tex]3( {x}^{2} - 4x + 4) + 1 = 13[/tex]
[tex] {3x}^{2} - 12x + 12 + 1 = 13[/tex]
[tex] {3x}^{2} - 12x + 13 = 13[/tex]
[tex] {3x}^{2} - 12x = 0[/tex]
[tex]x \times (x - 4) = 0[/tex]
[tex]x = 0[/tex]
[tex]x - 4 = 0[/tex]
[tex] \boxed{\green{x_{1} = 0. \: \: \: x_{2} = 4}}[/tex]