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Let the no be x
ATQ
[tex]\\ \sf\longmapsto \dfrac{x}{6}-11=1[/tex]
[tex]\\ \sf\longmapsto \dfrac{x-66}{6}=1[/tex]
[tex]\\ \sf\longmapsto x-66=6[/tex]
[tex]\\ \sf\longmapsto x=66+6[/tex]
[tex]\\ \sf\longmapsto x=72[/tex]