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Sagot :
let the consecutive even integers be 2x , 2x + 2 and 2x + 4
let's solve for values of the integers :
- [tex]2x + 2x + 2 + 2x + 4 = 36[/tex]
- [tex]6x + 6 = 36[/tex]
- [tex]6x = 36 - 6[/tex]
- [tex]x = \dfrac{30}{6} [/tex]
- [tex]x = 5[/tex]
therefore, the consecutive even integers are :
- [tex]2x = 2 \times 5 = 10[/tex]
- [tex]2x + 2 = 10 + 2 = 12[/tex]
- [tex]2x + 4 = 10 + 4 = 14[/tex]
I hope it helped...
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