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Find the quotient. 14x^3 – 21x² +28x )÷ (7x)​

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AlgebraicAardvarkidn

To find the quotient [tex]\dfrac{14x^3 -21x^2 + 28x}{7x}[/tex], you can break this into three separate fractions, each over [tex]7x[/tex]:

    [tex]\dfrac{14x^3 -21x^2 + 28x}{7x} =~ \dfrac{14x^3}{7x} ~-~\dfrac{ 21x^2}{7x} ~+~\dfrac{28x}{7x}[/tex]

Now you need to just divide the 7 into each coefficient in the numerator and then cancel out x's as appropriate.

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