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Approximately 9% of people are left-handed. If two people are selected at random, what is the probability that at least one is right-handed? (Round your answer to 4 decimal places.)

Sagot :

MrRoyalidn

Probabilities are used to determine the possibility of an event.

The probability that at least one of the selected two is right-handed is 0.9919

Let

[tex]p \to[/tex] left-handed people

[tex]q \to[/tex] right-handed people

So, we have:

[tex]p = 9\%[/tex]

The probability that at least one is right-handed is calculated as follows:

[tex]Pr =1 - P(None)[/tex] --- Complement rule

Where:

[tex]P(None) \to[/tex] The probability that none of the selected 2 is right-handed; in other words, the selected 2 are left-handed.

So, we have:

[tex]P(None) = p \times p[/tex]

[tex]P(None) = 9\% \times 9\%[/tex]

[tex]P(None) = 0.0081[/tex]

Substitute [tex]P(None) = 0.0081[/tex] in [tex]Pr =1 - P(None)[/tex]

[tex]Pr = 1 - 0.0081[/tex]

[tex]Pr = 0.9919[/tex]

Hence, the probability that at least one of the selected two is right-handed is 0.9919

Read more about probability at:

https://brainly.com/question/24297863

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