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If an object is projected horizontally from a height of 5 m with an initial velocity of 7 m/s, what is the value of x0?x0=0x0=7x0=−9.8 m/sx0=5

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Okpalawalter8idn

We have that the value of x_0 is

[tex]x_0=7m[/tex]

From the question we are told that

height of 5 m

initial velocity of 7 m/s

[tex]x_0=7\\\\x_0=−9.8 m/s\\\\x_0=5[/tex]

From the correct diagram

Generally the equation for the Time   is mathematically given as

[tex]t=\sqrt{\frac{2h}{g}}\\\\x_0=7*\sqrt{\frac{2xh5}{9.8}}[/tex]

x_0=7m

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